(2y^2+2y-12)/(y^2-5y+6)

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Solution for (2y^2+2y-12)/(y^2-5y+6) equation:


D( y )

y^2-(5*y)+6 = 0

y^2-(5*y)+6 = 0

y^2-(5*y)+6 = 0

y^2-5*y+6 = 0

y^2-5*y+6 = 0

DELTA = (-5)^2-(1*4*6)

DELTA = 1

DELTA > 0

y = (1^(1/2)+5)/(1*2) or y = (5-1^(1/2))/(1*2)

y = 3 or y = 2

y in (-oo:2) U (2:3) U (3:+oo)

(2*y^2+2*y-12)/(y^2-(5*y)+6) = 0

(2*y^2+2*y-12)/(y^2-5*y+6) = 0

2*y^2+2*y-12 = 0

2*(y^2+y-6) = 0

y^2+y-6 = 0

DELTA = 1^2-(-6*1*4)

DELTA = 25

DELTA > 0

y = (25^(1/2)-1)/(1*2) or y = (-25^(1/2)-1)/(1*2)

y = 2 or y = -3

2*(y+3)*(y-2) = 0

y^2-5*y+6 = 0

y^2-5*y+6 = 0

DELTA = (-5)^2-(1*4*6)

DELTA = 1

DELTA > 0

y = (1^(1/2)+5)/(1*2) or y = (5-1^(1/2))/(1*2)

y = 3 or y = 2

(y-2)*(y-3) = 0

(2*(y+3)*(y-2))/((y-2)*(y-3)) = 0

( y+3 )

y+3 = 0 // - 3

y = -3

( y-2 )

y-2 = 0 // + 2

y = 2

y in { 2}

y = -3

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